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4(x-1/2)^2-3x+1=(2x+3)^2-19x+2
We move all terms to the left:
4(x-1/2)^2-3x+1-((2x+3)^2-19x+2)=0
We add all the numbers together, and all the variables
4(+x-1/2)^2-3x-((2x+3)^2-19x+2)+1=0
We add all the numbers together, and all the variables
-3x+4(+x-1/2)^2-((2x+3)^2-19x+2)+1=0
We multiply all the terms by the denominator
-3x*2)^2+4(+x-(((2x+3)^2-19x+2))*2)^2+1*2)^2-1=0
We add all the numbers together, and all the variables
x-3x*2)^2+4(-(((2x+3)^2-19x+2))*2)^2+1*2)^2-1=0
Wy multiply elements
-6x^2+x-(((2x+3)^2-19x+2))*2)^2+1*2)^2-1=0
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